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json debug, 404

This commit is contained in:
j 2010-01-29 16:50:24 +05:30
parent 1b5ec862af
commit a9398240d3
1 changed files with 15 additions and 3 deletions
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18
oxdjango/shortcuts.py
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@ -1,7 +1,7 @@
# -*- coding: utf-8 -*-
# vi:si:et:sw=4:sts=4:ts=4
from django.http import HttpResponse
from django.http import HttpResponse, Http404
try:
import simplejson
except ImportError:
@ -13,8 +13,20 @@ def render_to_json_response(dictionary, content_type="text/json", status=200):
if settings.DEBUG:
content_type = "text/javascript"
indent = 2
print simplejson.dumps(dictionary, indent=indent)
if settings.JSON_DEBUG:
print simplejson.dumps(dictionary, indent=2)
if 'status' in dictionary and 'code' in dictionary['status']:
status = dictionary['status']['code']
return HttpResponse(simplejson.dumps(dictionary, indent=indent), content_type=content_type, status=status)
return HttpResponse(simplejson.dumps(dictionary, indent=indent),
content_type=content_type, status=status)
def get_object_or_404_json(klass, *args, **kwargs):
from django.shortcuts import _get_queryset
queryset = _get_queryset(klass)
try:
return queryset.get(*args, **kwargs)
except queryset.model.DoesNotExist:
#FIXME: how to raise exception that will only output given result
results = simplejson.dumps({'status': {'code': 404,
'text': '%s not found' % queryset.model._meta.object_name}})
raise Http404(results)