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don't print status during upload

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j 2021-02-19 00:10:59 +01:00
parent 2ebc6ffd3a
commit f7c7a6689b
1 changed files with 11 additions and 6 deletions
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7
ox/api.py
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@ -151,7 +151,7 @@ class API(object):
fd.write(chunk)
shutil.move(tmpname, filename)
def upload_chunks(self, url, filename, data=None):
def upload_chunks(self, url, filename, data=None, silent=False):
form = MultiPartForm()
if data:
for key in data:
@ -188,18 +188,22 @@ class API(object):
try:
data = self._json_request(uploadUrl, form)
except KeyboardInterrupt:
if not slient:
print("\ninterrupted by user.")
sys.exit(1)
except:
if not slient:
print("uploading chunk failed, will try again in 5 seconds\r", end='')
sys.stdout.flush()
data = {'result': -1}
time.sleep(5)
if data and 'status' in data:
if data['status']['code'] == 403:
if not slient:
print("login required")
return False
if data['status']['code'] != 200:
if not slient:
print("request returned error, will try again in 5 seconds")
if self.DEBUG:
print(data)
@ -207,6 +211,7 @@ class API(object):
if data and data.get('result') == 1:
done += len(chunk)
if data.get('offset') not in (None, done):
if not slient:
print('server offset out of sync, continue from', data['offset'])
done = data['offset']
f.seek(done)