custom queryset to allow for order by NULLS LAST

This commit is contained in:
j 2011-01-25 04:13:00 +05:30
parent e404521e11
commit 437d90a00f

61
ox/django/query.py Normal file
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@ -0,0 +1,61 @@
# -*- coding: utf-8 -*-
# vi:si:et:sw=4:sts=4:ts=4
from django.db.models.query import QuerySet
from django.db.models.sql import Query
from django.db.models.sql.compiler import SQLCompiler
from django.db import connections
'''
models.py:
-----------------------------------
from ox.django.query import QuerySet
class Manager(models.Manager):
def get_query_set(self):
return QuerySet(self.model)
class Model(models.Model):
...
objects = Manager()
'''
class SQLCompiler(SQLCompiler):
def get_ordering(self):
result, group_by = super(SQLCompiler, self).get_ordering()
if self.query.nulls_last and len(result):
result = map(lambda e: e + ' NULLS LAST', result)
return result, group_by
class Query(Query):
nulls_last = False
def clone(self, *args, **kwargs):
obj = super(Query, self).clone(*args, **kwargs)
obj.nulls_last = self.nulls_last
return obj
def get_compiler(self, using=None, connection=None):
if using is None and connection is None:
raise ValueError("Need either using or connection")
if using:
connection = connections[using]
# Check that the compiler will be able to execute the query
for alias, aggregate in self.aggregate_select.items():
connection.ops.check_aggregate_support(aggregate)
return SQLCompiler(self, connection, using)
class QuerySet(QuerySet):
def __init__(self, model=None, query=None, using=None):
super(QuerySet, self).__init__(model=model, query=query, using=None)
self.query = query or Query(self.model)
def order_by(self, *args, **kwargs):
nulls_last = kwargs.pop('nulls_last', False)
obj = super(QuerySet, self).order_by(*args, **kwargs)
obj.query.nulls_last = nulls_last
return obj