').addClass('sign').hide().appendTo($body),
$images = [],
lines, mapSize, poles;
/*
Ox.getPoint takes a lat/lng pair, a distance and a bearing, and returns the
resulting point. We use this to construct the origin of the coordinate
system, by moving Columbus Circle by minus 59 streets in the direction of
the avenues and then by minus 8 avenues in the direction of the streets.
The resulting point is on Stanton St between Norfolk St and Suffolk St,
which is pretty close to where we expected it to be.
*/
points['0 & 0'] = Ox.getPoint(
Ox.getPoint(
points['8 & 59'],
-59 * distances.streets,
bearings.avenues
),
-8 * distances.avenues,
bearings.streets
);
/*
The second intersection of Zero Ave, Zero St and Broadway is half of the
Earth's circumference away from the first one, in any direction.
*/
points['-0 & -0'] = Ox.getPoint(
points['0 & 0'],
Ox.EARTH_CIRCUMFERENCE / 2,
0
);
/*
Now that we have constructed the origin, we can calculate the bearing of
Broadway, which runs from Zero & Zero through Columbus Circle.
*/
bearings.broadway = Ox.getBearing(points['0 & 0'], points['8 & 59']),
/*
Also, we can construct the poles, each of which is a quarter of Earth's
circumference away from Zero & Zero.
*/
poles = {
north: Ox.getPoint(points['0 & 0'], C / 4, bearings.avenues),
south: Ox.getPoint(points['0 & 0'], -C / 4, bearings.avenues),
west: Ox.getPoint(points['0 & 0'], C / 4, bearings.streets),
east: Ox.getPoint(points['0 & 0'], -C / 4, bearings.streets),
/*
Broadway has two poles as well, and constructing them will make drawing
easier. Ox.mod is the modulo function. Unlike `-90 % 360`,
which in JavaScript is -90, Ox.mod(-90, 360) returns 270.
*/
westBroadway: Ox.getPoint(
points['0 & 0'],
C / 4,
Ox.mod(bearings.broadway - 90, 360)
),
eastBroadway: Ox.getPoint(
points['0 & 0'],
C / 4,
Ox.mod(bearings.broadway + 90, 360)
)
};
/*
Now we calculate circles for Broadway, Avenues and Streets. Ox.getCircle
returns an array of lat/lng pairs that form a circle around a given point,
with a given radius and a given precision, so that the circle will have
`Math.pow(2, precision)` segments.
*/
lines = {
/*
Since there is only one Broadway, this is an array with just one circle
that runs around one of the Broadway Poles, at a distance of a quarter
of the Earth's circumference.
*/
broadway: [Ox.getCircle(poles.westBroadway, C / 4, precision)],
/*
For each 10,000th avenue, we compute a circle around the East Pole.
From there, avenues range from -34,966th to 34,966th, so we start at a
distance of 966 avenues from the pole, stop once the distance is half
of the Earth's circumference (the West Pole), and in each step increase
the distance by 10,000 avenues.
*/
avenues: Ox.range(
distances.avenues * (numbers.avenues % step),
C / 2,
distances.avenues * step
).map(function(distance) {
return Ox.getCircle(poles.east, distance, precision);
}),
/*
Then we do the same for streets, starting at the South Pole.
*/
streets: Ox.range(
distances.streets * (numbers.streets % step),
C / 2,
distances.streets * step
).map(function(distance) {
return Ox.getCircle(poles.south, distance, precision);
})
};
/*
Print our data to the console.
*/
Ox.print(JSON.stringify({
bearings: bearings,
distances: distances,
numbers: numbers,
points: points,
poles: poles
}, null, ' '));
/*
Before we start drawing, we define a few helper functions.
`getXYByLatLng` returns screen coordinates for a given point.
We use Ox.getXYByLatLng, which takes a lat/lng pair and returns its x/y
position on a 1×1 Mercator position, with `{x: 0, y: 0}` at the
bottom left and `{x: 1, y: 1}` at the top right.
*/
function getXYByLatLng(point) {
return Ox.map(Ox.getXYByLatLng(point), function(v) {
return v * mapSize;
});
}
/*
`getLatLngByXY` is the inverse of the above, just like
Ox.getLatLngByXY.
*/
function getLatLngByXY(xy) {
return Ox.getLatLngByXY(Ox.map(xy, function(v) {
return v / mapSize;
}));
}
/*
`getASByLatLng` takes lat/lng and returns avenue/street. To
compute the avenue, we subtract the point's distance from the West Pole, in
avenues, from the total number of avenues. To compute the street, we
subtract the point's distance from the North Pole, in avenues, from the
total number of streets. We also return the bearing of the avenues at this
point (which form a right angle with the line from the point to the West
Pole), the bearing of the streets (at a right angle with the line to the
North Pole) and the hemisphere (east or west of Broadway).
*/
function getASByLatLng(point) {
var n = Ox.getDistance(point, poles.north),
w = Ox.getDistance(point, poles.west);
return {
avenue: numbers.avenues - w / distances.avenues,
street: numbers.streets - n / distances.streets,
bearings: {
avenues: Ox.mod(Ox.getBearing(point, poles.west) + (
w < C / 4 ? -90 : 90
), 360),
streets: Ox.mod(Ox.getBearing(point, poles.north) + (
n < C / 4 ? -90 : 90
), 360)
},
hemisphere: Ox.getDistance(point, poles.eastBroadway) < C / 4
? 'E' : 'W'
};
}
/*
`getASByXY` returns avenue and street at the given screen
coordinates.
*/
function getASByXY(xy) {
return getASByLatLng(getLatLngByXY(xy));
}
/*
`drawPath` draws a path of lat/lng pairs on an image. For each
path segment, we have to check if it crosses the eastern or western edge of
the map that splits the Pacific Ocean. Note that our test (a segment
crosses the edge if it spans more than 180 degrees longitude) is obviously
incorrect, but works in our case, since all segments are sufficiently
short.
*/
function drawPath(image, path, options) {
var n, parts = [[]];
/*
Close the path by appending the first point.
*/
path.push(path[0]);
n = path.length;
Ox.loop(n, function(i) {
var lat, lng, split;
/*
Append each point to the last part.
*/
Ox.last(parts).push(path[i]);
if (Math.abs(path[i].lng - path[(i + 1) % n].lng) > 180) {
/*
If the next line crosses the edge, get the lat/lng of the
points where the line leaves and enters the map.
*/
lat = Ox.getCenter(path[i], path[i + 1]).lat;
lng = path[i].lng < 0 ? [-180, 180] : [180, -180];
/*
Append the first point to the last part and create a new part
with the second point.
*/
Ox.last(parts).push({lat: lat, lng: lng[0]});
parts.push([{lat: lat, lng: lng[1]}]);
}
});
/*
We draw each part, translating lat/lng to [x, y].
*/
parts.forEach(function(part) {
image.drawPath(part.map(function(point) {
var xy = getXYByLatLng(point);
return [xy.x, xy.y];
}), options);
});
}
/*
Now it's time to load our map image.
*/
Ox.Image('jpg/earth1024.jpg', function(image) {
mapSize = image.getSize().width;
/*
First, we draw a circle, centered at the intersection of Zero Ave and
Zero St, with a radius of the quarter of the Earth's circumference. This
is the line that runs through all four poles of our coordinate system.
*/
drawPath(image, Ox.getCircle(points['0 & 0'], C / 4, 8), {
color: 'rgba(255, 255, 255, 0.25)'
});
/*
Then, we draw the streets, avenues and Broadway. Zero St, Zero Ave and
Broadway will be twice as bold as the others.
*/
['streets', 'avenues', 'broadway'].forEach(function(type) {
lines[type].forEach(function(line, i) {
drawPath(image, line, {
color: colors[type],
width: i == lines[type].length / 2 - 0.5 ? 2 : 1
});
});
});
/*
Now we load the map image as the background of our document, and attach
a few event handlers.
*/
$body.css({
minWidth: mapSize + 'px',
height: mapSize + 'px',
backgroundImage: 'url(' + image.src() + ')'
})
.on({
click: onClick,
mouseover: onMouseover,
mousemove: onMousemove,
mouseout: onMouseout
});
/*
As an extra feature, we want to provide more detailed renderings at a
higher zoom level, for three points of interest. (Our point in Paris is
the closest Manhattan Grid intersection to the Étoile, a real-world
intersection of twelve large avenues.)
*/
points['Paris'] = {lat: 48.87377, lng: 2.29505};
[
{point: points['0 & 0'], title: 'Manhattan', z: 12},
{point: getIntersection(points['Paris']), title: 'Paris', z: 13},
{point: poles.north, title: 'Uzbekistan', z: 14}
].forEach(function(marker, i) {
/*
We're trying to make this function as generic as possible: for any
given point and zoom level, it would allow us the retrieve the
corresponding Google Maps tile. Even though we are just using three
local images here, their naming scheme matches the logic of Google
Maps. Manhattan, for example, is "jpg/v=108&x=1206&y=1539&z=12.jpg".
*/
var as = getASByLatLng(marker.point),
g = {s: 256, v: 108, z: marker.z},
xy = getXYByLatLng(marker.point);
Ox.extend(g, Ox.map(Ox.getXYByLatLng(marker.point), function(v) {
return Math.floor(v * Math.pow(2, g.z));
}));
/*
For each point, we add a marker, with a click handler that will
display the corresponding image.
*/
Ox.$('
')
.addClass('marker')
.css({
left: xy.x - 4 + 'px',
top: xy.y - 4 + 'px'
})
.on({
click: function() {
$images.forEach(function($image) {
$image.hide();
});
$images[i].show();
}
})
.appendTo($body);
/*
Now we load the image.
*/
Ox.Image(Ox.formatString(
'jpg/v={v}&x={x}&y={y}&z={z}.jpg', g
), function(image) {
/*
First, we draw the streets.
*/
if (marker.title == 'Uzbekistan') {
/*
Uzbekistan, the North Pole of our projection, is a special
case, as the streets run in circles around it. (The exact
number of streets is a float — 123582.49214895045
— so the radius of the northernmost street —
123,582th St — is 0.492 times the distance between
streets.)
*/
Ox.loop(
distances.streets * (numbers.streets % 1),
2000,
distances.streets,
function(distance) {
var circle = mapLine(Ox.getCircle(
poles.north, distance, precision
), g);
image.drawPath(circle, {
close: true,
color: colors.streets
});
}
);
} else {
/*
Otherwise, we draw all streets from 200 streets "south" to
200 steets "north" of the point, using `getLine`, a helper
function defined below.
*/
Ox.loop(-200, 200, function(street) {
var line = getLine(
g, marker.point, as, 'streets', street
);
image.drawPath(line, {
color: colors.streets,
width: marker.title == 'Paris' || street ? 1 : 2
});
});
}
/*
Next, we draw all avenues from 20 avenues "east" to 20 avenues
"west" of the point.
*/
Ox.loop(-20, 20, function(avenue) {
var line = getLine(g, marker.point, as, 'avenues', avenue);
image.drawPath(line, {
color: colors.avenues,
width: marker.title == 'Paris' || avenue ? 1 : 2
});
});
/*
Then, on the Manhattan tile, we draw Broadway, too.
*/
if (marker.title == 'Manhattan') {
var line = mapLine(Ox.getLine(
Ox.getPoint(marker.point, -10000, bearings.broadway),
Ox.getPoint(marker.point, 10000, bearings.broadway),
1
), g);
image.drawPath(line, {
color: 'rgba(0, 0, 255, 0.5)',
width: 2
});
}
/*
Finally, we add the place name (white text with a black shadow).
*/
['black', 'white'].forEach(function(color, i) {
image.drawText(marker.title, [240 - i, 240 - i], {
color: color,
font: 'bold 16px Lucida Grande, sans-serif',
textAlign: 'right'
});
});
/*
Now we can put the image into the DOM.
*/
$images[i] = Ox.$('![]()
')
.attr({src: image.src()})
.hide()
.appendTo($body);
});
});
});
/*
`getIntersection` is a helper function that returns the coordinates of the
closest intersection from a given point.
*/
function getIntersection(point) {
var as = getASByLatLng(point), d = {};
['avenue', 'street'].forEach(function(type) {
var mod = Ox.mod(as[type], 1);
d[type] = ((mod < 0.5 ? 0 : 1) - mod) * distances[type + 's'];
});
return Ox.getPoint(
Ox.getPoint(
point,
d.street,
as.bearings.avenues
),
d.avenue,
as.bearings.streets
);
}
/*
`getLine` is a helper function that returns the i-th avenue or street from a
given point, as an array of x/y coordinates on the zoomed-in map tile.
*/
function getLine(g, point, as, type, i) {
point = Ox.getPoint(
point,
i * distances[type],
as.bearings[type == 'avenues' ? 'streets' : 'avenues']
);
return mapLine(Ox.getLine(
Ox.getPoint(point, -10000, as.bearings[type]),
Ox.getPoint(point, 10000, as.bearings[type]),
1
), g);
}
/*
`mapLine` is a helper function that, given a line of points (an array of
lat/lng pairs) and an object `g` with the properties `lat`, `lng`, `s`
(tile size) and `z` (zoom level), maps the line to an array of x/y
coordinates on the zoomed-in map tile.
*/
function mapLine(line, g) {
return line.map(function(point) {
var xy = Ox.map(Ox.getXYByLatLng(point), function(value, key) {
return (value * Math.pow(2, g.z) - g[key]) * g.s;
});
return [xy.x, xy.y];
});
}
/*
Now all that's left is adding our event handlers. Clicking on any point of
the map that is not a marker will hide the currently visible overlay image
(if any).
*/
function onClick(e) {
if (e.target.className != 'marker') {
$images.forEach(function($image) {
$image.hide();
});
}
}
/*
When the mouse enters the map, show a street sign (which consists of a post
an the actual sign).
*/
function onMouseover() {
$post.show();
$sign.show();
}
/*
When the mouse moves on the map, update the street sign.
*/
function onMousemove(e) {
/*
In case the mouse is on the overlay image, hide the sign and return.
*/
if (e.target.tagName == 'IMG') {
onMouseout();
return;
}
var left = window.scrollX,
right = left + window.innerWidth,
top = window.scrollY,
/*
`xy` is the actual map pixel the mouse is pointing at...
*/
xy = {x: left + e.clientX, y: top + e.clientY},
/*
... `latlng` is the latitude and longitude of that point ...
*/
latlng = getLatLngByXY(xy),
/*
... and `as` is the equivalent in avenues and streets.
*/
as = getASByXY(xy),
width, height, invertX, invertY;
/*
On the street sign, we display both the avenue/street and the lat/lng
coordinates.
*/
$sign.html(
Ox.formatNumber(as.avenue, 0) + 'th Av & '
+ as.hemisphere + ' '
+ Ox.formatNumber(as.street, 0) + 'th St'
+ '
'
+ Ox.formatDegrees(latlng.lat, 'lat') + ' / '
+ Ox.formatDegrees(((latlng.lng + 180) % 360) - 180, 'lng')
+ '
'
);
/*
As the street sign extends to the top and right of the mouse position,
we have to invert its direction in case the mouse is close to the top or
right edge of the window.
*/
width = $sign.width();
height = $sign.height();
invertX = xy.x + width > right;
invertY = xy.y - height - 32 < top;
$sign.css({
left: xy.x + (invertX ? 1 - width : -1) + 'px',
top: xy.y + (invertY ? 32 : -32 - height) + 'px'
});
$post.css({
left: xy.x - 1 + 'px',
top: xy.y + (invertY ? 0 : -32 - height) + 'px',
height: height + 32 + 'px'
});
}
/*
When the mouse leaves the map, hide the street sign.
*/
function onMouseout() {
$post.hide();
$sign.hide();
}
/*
And that's it!
*/
});