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remove 'Ox.starts' and 'Ox.ends' aliases, update documentation; fix Ox.pad with negative length

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rolux 2012-06-04 11:22:40 +02:00
parent a5c6747b57
commit cd8b2e297d
1 changed files with 15 additions and 13 deletions
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28
source/Ox/js/String.js
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@ -36,14 +36,15 @@ Ox.clean = function(string) {
}; };
/*@ /*@
Ox.endsWith <f> Checks if a string ends with a given substring Ox.endsWith <f> Tests if a string ends with a given substring
If the substring is a string literal (and not a variable), Equivalent to `new RegExp(Ox.escapeRegExp(substring) + '$').test(string)`.
`/sub$/.test(str)` or `!!/sub$/.exec(str)` is shorter than `Ox.ends(str, (string, substring) -> <b> True if string ends with substring
sub)`.
> Ox.endsWith('foobar', 'bar') > Ox.endsWith('foobar', 'bar')
true true
> Ox.endsWith('foobar', 'foo')
false
@*/ @*/
Ox.ends = Ox.endsWith = function(string, substring) { Ox.endsWith = function(string, substring) {
string = string.toString(); string = string.toString();
substring = substring.toString(); substring = substring.toString();
return string.slice(string.length - substring.length) == substring; return string.slice(string.length - substring.length) == substring;
@ -100,14 +101,15 @@ Ox.pad <f> Pad a string to a given length
'foo' 'foo'
> Ox.pad('foobar', 'left', 3) > Ox.pad('foobar', 'left', 3)
'bar' 'bar'
> Ox.pad('foo', -1)
''
@*/ @*/
Ox.pad = function(string, position, length, padding) { Ox.pad = function(string, position, length, padding) {
// fixme: weird for negative numbers
var hasPosition = Ox.isString(arguments[1]), var hasPosition = Ox.isString(arguments[1]),
isNumber = Ox.isNumber(arguments[0]), isNumber = Ox.isNumber(arguments[0]),
last = Ox.last(arguments); last = Ox.last(arguments);
position = hasPosition ? arguments[1] : isNumber ? 'left' : 'right'; position = hasPosition ? arguments[1] : isNumber ? 'left' : 'right';
length = hasPosition ? arguments[2] : arguments[1]; length = Math.max(hasPosition ? arguments[2] : arguments[1], 0);
padding = Ox.isString(last) ? last padding = Ox.isString(last) ? last
: isNumber && position == 'left' ? '0' : ' '; : isNumber && position == 'left' ? '0' : ' ';
string = string.toString(); string = string.toString();
@ -410,15 +412,15 @@ Ox.splice = function(string, index, remove) {
}; };
/*@ /*@
Ox.startsWith <f> Checks if a string starts with a given substring Ox.startsWith <f> Tests if a string ends with a given substring
If the substring is a string literal (and not a variable), Equivalent to `new RegExp('^' + Ox.escapeRegExp(substring)).test(string)`.
`/^sub/.test(str)` or `!!/^sub/.exec(str)` is shorter than `Ox.starts(str, (string, substring) -> <b> True if string starts with substring
sub)`.
> Ox.startsWith('foobar', 'foo') > Ox.startsWith('foobar', 'foo')
true true
> Ox.startsWith('foobar', 'bar')
false
@*/ @*/
Ox.starts = Ox.startsWith = function(string, substring) { Ox.startsWith = function(string, substring) {
// fixme: rename to starts
string = string.toString(); string = string.toString();
substring = substring.toString(); substring = substring.toString();
return string.slice(0, substring.length) == substring; return string.slice(0, substring.length) == substring;