update examples
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2 changed files with 7 additions and 8 deletions
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@ -51,7 +51,7 @@ Ox.load('Image', function() {
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/*
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Ox.getXYByLatLng takes a lat/lng pair and returns its x/y position on a
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1x1 Mercator position, <code>{x: 0, y: 0}</code> being the bottom left,
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1×1 Mercator position, <code>{x: 0, y: 0}</code> being the bottom left,
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<code>{x: 1, y: 1}</code> being the top right.
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*/
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function getXY(point) {
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@ -87,12 +87,10 @@ Ox.load('Image', function() {
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parts[0].push({lat: lat, lng: lng[0]});
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parts[1].unshift({lat: lat, lng: lng[1]});
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/*
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Returning false from Ox.loop is the equivalent of
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<code>break</code> in a <code>for</code> loop. Again, note
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that this assumes no path will cross the edge more than
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once.
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Ox.Break() breaks the loop. Again, note that this assumes no
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path will cross the edge more than once.
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*/
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return false;
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Ox.Break();
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}
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});
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/*
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@ -211,7 +211,7 @@ Ox.load('Image', function() {
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Before we start drawing, we define a few helper functions.
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<code>getXYByLatLng</code> returns screen coordinates for a given point.
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We use Ox.getXYByLatLng, which takes a lat/lng pair and returns its x/y
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position on a 1x1 Mercator position, with <code>{x: 0, y: 0}</code> at the
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position on a 1×1 Mercator position, with <code>{x: 0, y: 0}</code> at the
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bottom left and <code>{x: 1, y: 1}</code> at the top right.
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*/
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function getXYByLatLng(point) {
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@ -221,7 +221,8 @@ Ox.load('Image', function() {
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}
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/*
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<code>getLatLngByXY</code> is just the inverse, just like Ox.getLatLngByXY.
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<code>getLatLngByXY</code> is the inverse of the above, just like
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Ox.getLatLngByXY.
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*/
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function getLatLngByXY(xy) {
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return Ox.getLatLngByXY(Ox.map(xy, function(v) {
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