Metadata-Version: 2.1 Name: netifaces Version: 0.10.9 Summary: Portable network interface information. Home-page: https://github.com/al45tair/netifaces Author: Alastair Houghton Author-email: alastair@alastairs-place.net License: MIT License Platform: UNKNOWN Classifier: Development Status :: 4 - Beta Classifier: Intended Audience :: Developers Classifier: License :: OSI Approved :: MIT License Classifier: Topic :: System :: Networking Classifier: Programming Language :: Python Classifier: Programming Language :: Python :: 2 Classifier: Programming Language :: Python :: 2.5 Classifier: Programming Language :: Python :: 2.6 Classifier: Programming Language :: Python :: 2.7 Classifier: Programming Language :: Python :: 3 Classifier: Programming Language :: Python :: 3.4 Classifier: Programming Language :: Python :: 3.5 Classifier: Programming Language :: Python :: 3.6 netifaces 0.10.8 ================ +-------------+------------------+ | Linux/macOS | |BuildStatus| | +-------------+------------------+ | Windows | |WinBuildStatus| | +-------------+------------------+ .. |BuildStatus| image:: https://travis-ci.org/al45tair/netifaces.svg?branch=master :target: https://travis-ci.org/al45tair/dmgbuild :alt: Build Status (Linux/Mac) .. |WinBuildStatus| image:: https://ci.appveyor.com/api/projects/status/3ctn1bl0aigpfjoo/branch/master?svg=true :target: https://ci.appveyor.com/project/al45tair/netifaces/branch/master :alt: Build Status (Windows) 1. What is this? ---------------- It's been annoying me for some time that there's no easy way to get the address(es) of the machine's network interfaces from Python. There is a good reason for this difficulty, which is that it is virtually impossible to do so in a portable manner. However, it seems to me that there should be a package you can easy_install that will take care of working out the details of doing so on the machine you're using, then you can get on with writing Python code without concerning yourself with the nitty gritty of system-dependent low-level networking APIs. This package attempts to solve that problem. 2. How do I use it? ------------------- First you need to install it, which you can do by typing:: tar xvzf netifaces-0.10.8.tar.gz cd netifaces-0.10.8 python setup.py install **Note that you will need the relevant developer tools for your platform**, as netifaces is written in C and installing this way will compile the extension. Once that's done, you'll need to start Python and do something like the following:: >>> import netifaces Then if you enter >>> netifaces.interfaces() ['lo0', 'gif0', 'stf0', 'en0', 'en1', 'fw0'] you'll see the list of interface identifiers for your machine. You can ask for the addresses of a particular interface by doing >>> netifaces.ifaddresses('lo0') {18: [{'addr': ''}], 2: [{'peer': '127.0.0.1', 'netmask': '255.0.0.0', 'addr': '127.0.0.1'}], 30: [{'peer': '::1', 'netmask': 'ffff:ffff:ffff:ffff:ffff:ffff:ffff:ffff', 'addr': '::1'}, {'peer': '', 'netmask': 'ffff:ffff:ffff:ffff::', 'addr': 'fe80::1%lo0'}]} Hmmmm. That result looks a bit cryptic; let's break it apart and explain what each piece means. It returned a dictionary, so let's look there first:: { 18: [...], 2: [...], 30: [...] } Each of the numbers refers to a particular address family. In this case, we have three address families listed; on my system, 18 is ``AF_LINK`` (which means the link layer interface, e.g. Ethernet), 2 is ``AF_INET`` (normal Internet addresses), and 30 is ``AF_INET6`` (IPv6). But wait! Don't use these numbers in your code. The numeric values here are system dependent; fortunately, I thought of that when writing netifaces, so the module declares a range of values that you might need. e.g. >>> netifaces.AF_LINK 18 Again, on your system, the number may be different. So, what we've established is that the dictionary that's returned has one entry for each address family for which this interface has an address. Let's take a look at the ``AF_INET`` addresses now: >>> addrs = netifaces.ifaddresses('lo0') >>> addrs[netifaces.AF_INET] [{'peer': '127.0.0.1', 'netmask': '255.0.0.0', 'addr': '127.0.0.1'}] You might be wondering why this value is a list. The reason is that it's possible for an interface to have more than one address, even within the same family. I'll say that again: *you can have more than one address of the same type associated with each interface*. *Asking for "the" address of a particular interface doesn't make sense.* Right, so, we can see that this particular interface only has one address, and, because it's a loopback interface, it's point-to-point and therefore has a *peer* address rather than a broadcast address. Let's look at a more interesting interface. >>> addrs = netifaces.ifaddresses('en0') >>> addrs[netifaces.AF_INET] [{'broadcast': '10.15.255.255', 'netmask': '255.240.0.0', 'addr': '10.0.1.4'}, {'broadcast': '192.168.0.255', 'addr': '192.168.0.47'}] This interface has two addresses (see, I told you...) Both of them are regular IPv4 addresses, although in one case the netmask has been changed from its default. The netmask *may not* appear on your system if it's set to the default for the address range. Because this interface isn't point-to-point, it also has broadcast addresses. Now, say we want, instead of the IP addresses, to get the MAC address; that is, the hardware address of the Ethernet adapter running this interface. We can do >>> addrs[netifaces.AF_LINK] [{'addr': '00:12:34:56:78:9a'}] Note that this may not be available on platforms without getifaddrs(), unless they happen to implement ``SIOCGIFHWADDR``. Note also that you just get the address; it's unlikely that you'll see anything else with an ``AF_LINK`` address. Oh, and don't assume that all ``AF_LINK`` addresses are Ethernet; you might, for instance, be on a Mac, in which case: >>> addrs = netifaces.ifaddresses('fw0') >>> addrs[netifaces.AF_LINK] [{'addr': '00:12:34:56:78:9a:bc:de'}] No, that isn't an exceptionally long Ethernet MAC address---it's a FireWire address. As of version 0.10.0, you can also obtain a list of gateways on your machine: >>> netifaces.gateways() {2: [('10.0.1.1', 'en0', True), ('10.2.1.1', 'en1', False)], 30: [('fe80::1', 'en0', True)], 'default': { 2: ('10.0.1.1', 'en0'), 30: ('fe80::1', 'en0') }} This dictionary is keyed on address family---in this case, ``AF_INET``---and each entry is a list of gateways as ``(address, interface, is_default)`` tuples. Notice that here we have two separate gateways for IPv4 (``AF_INET``); some operating systems support configurations like this and can either route packets based on their source, or based on administratively configured routing tables. For convenience, we also allow you to index the dictionary with the special value ``'default'``, which returns a dictionary mapping address families to the default gateway in each case. Thus you can get the default IPv4 gateway with >>> gws = netifaces.gateways() >>> gws['default'][netifaces.AF_INET] ('10.0.1.1', 'en0') Do note that there may be no default gateway for any given address family; this is currently very common for IPv6 and much less common for IPv4 but it can happen even for ``AF_INET``. BTW, if you're trying to configure your machine to have multiple gateways for the same address family, it's a very good idea to check the documentation for your operating system *very* carefully, as some systems become extremely confused or route packets in a non-obvious manner. I'm very interested in hearing from anyone (on any platform) for whom the ``gateways()`` method doesn't produce the expected results. It's quite complicated extracting this information from the operating system (whichever operating system we're talking about), and so I expect there's at least one system out there where this just won't work. 3. This is great! What platforms does it work on? -------------------------------------------------- It gets regular testing on OS X, Linux and Windows. It has also been used successfully on Solaris, and it's expected to work properly on other UNIX-like systems as well. If you are running something that is not supported, and wish to contribute a patch, please use Github to send a pull request. 4. What license is this under? ------------------------------ It's an MIT-style license. See `LICENSE <./LICENSE>`_. 5. Why the jump to 0.10.0? -------------------------- Because someone released a fork of netifaces with the version 0.9.0. Hopefully skipping the version number should remove any confusion. In addition starting with 0.10.0 Python 3 is now supported and other features/bugfixes have been included as well. See the CHANGELOG for a more complete list of changes.