2016-02-06 09:36:57 +00:00
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"""
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Basic statistics module.
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This module provides functions for calculating statistics of data, including
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averages, variance, and standard deviation.
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Calculating averages
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--------------------
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================== =============================================
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Function Description
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================== =============================================
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mean Arithmetic mean (average) of data.
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2018-12-31 23:25:26 +00:00
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harmonic_mean Harmonic mean of data.
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2016-02-06 09:36:57 +00:00
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median Median (middle value) of data.
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median_low Low median of data.
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median_high High median of data.
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median_grouped Median, or 50th percentile, of grouped data.
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mode Mode (most common value) of data.
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================== =============================================
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Calculate the arithmetic mean ("the average") of data:
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>>> mean([-1.0, 2.5, 3.25, 5.75])
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2.625
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Calculate the standard median of discrete data:
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>>> median([2, 3, 4, 5])
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3.5
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Calculate the median, or 50th percentile, of data grouped into class intervals
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centred on the data values provided. E.g. if your data points are rounded to
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the nearest whole number:
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>>> median_grouped([2, 2, 3, 3, 3, 4]) #doctest: +ELLIPSIS
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2.8333333333...
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This should be interpreted in this way: you have two data points in the class
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interval 1.5-2.5, three data points in the class interval 2.5-3.5, and one in
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the class interval 3.5-4.5. The median of these data points is 2.8333...
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Calculating variability or spread
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---------------------------------
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================== =============================================
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Function Description
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================== =============================================
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pvariance Population variance of data.
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variance Sample variance of data.
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pstdev Population standard deviation of data.
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stdev Sample standard deviation of data.
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================== =============================================
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Calculate the standard deviation of sample data:
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>>> stdev([2.5, 3.25, 5.5, 11.25, 11.75]) #doctest: +ELLIPSIS
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4.38961843444...
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If you have previously calculated the mean, you can pass it as the optional
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second argument to the four "spread" functions to avoid recalculating it:
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>>> data = [1, 2, 2, 4, 4, 4, 5, 6]
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>>> mu = mean(data)
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>>> pvariance(data, mu)
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2.5
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Exceptions
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----------
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A single exception is defined: StatisticsError is a subclass of ValueError.
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"""
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__all__ = [ 'StatisticsError',
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'pstdev', 'pvariance', 'stdev', 'variance',
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'median', 'median_low', 'median_high', 'median_grouped',
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2018-12-31 23:25:26 +00:00
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'mean', 'mode', 'harmonic_mean',
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2016-02-06 09:36:57 +00:00
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]
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import collections
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import math
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2018-12-31 23:25:26 +00:00
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import numbers
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2016-02-06 09:36:57 +00:00
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from fractions import Fraction
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from decimal import Decimal
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2018-12-31 23:25:26 +00:00
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from itertools import groupby
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from bisect import bisect_left, bisect_right
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2016-02-06 09:36:57 +00:00
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# === Exceptions ===
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class StatisticsError(ValueError):
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pass
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# === Private utilities ===
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def _sum(data, start=0):
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2018-12-31 23:25:26 +00:00
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"""_sum(data [, start]) -> (type, sum, count)
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Return a high-precision sum of the given numeric data as a fraction,
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together with the type to be converted to and the count of items.
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2016-02-06 09:36:57 +00:00
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2018-12-31 23:25:26 +00:00
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If optional argument ``start`` is given, it is added to the total.
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If ``data`` is empty, ``start`` (defaulting to 0) is returned.
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2016-02-06 09:36:57 +00:00
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Examples
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--------
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>>> _sum([3, 2.25, 4.5, -0.5, 1.0], 0.75)
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2018-12-31 23:25:26 +00:00
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(<class 'float'>, Fraction(11, 1), 5)
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2016-02-06 09:36:57 +00:00
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Some sources of round-off error will be avoided:
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2018-12-31 23:25:26 +00:00
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# Built-in sum returns zero.
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>>> _sum([1e50, 1, -1e50] * 1000)
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(<class 'float'>, Fraction(1000, 1), 3000)
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2016-02-06 09:36:57 +00:00
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Fractions and Decimals are also supported:
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>>> from fractions import Fraction as F
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>>> _sum([F(2, 3), F(7, 5), F(1, 4), F(5, 6)])
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(<class 'fractions.Fraction'>, Fraction(63, 20), 4)
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2016-02-06 09:36:57 +00:00
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>>> from decimal import Decimal as D
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>>> data = [D("0.1375"), D("0.2108"), D("0.3061"), D("0.0419")]
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>>> _sum(data)
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2018-12-31 23:25:26 +00:00
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(<class 'decimal.Decimal'>, Fraction(6963, 10000), 4)
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2016-02-06 09:36:57 +00:00
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Mixed types are currently treated as an error, except that int is
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allowed.
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"""
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2018-12-31 23:25:26 +00:00
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count = 0
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2016-02-06 09:36:57 +00:00
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n, d = _exact_ratio(start)
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2018-12-31 23:25:26 +00:00
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partials = {d: n}
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2016-02-06 09:36:57 +00:00
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partials_get = partials.get
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2018-12-31 23:25:26 +00:00
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T = _coerce(int, type(start))
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for typ, values in groupby(data, type):
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T = _coerce(T, typ) # or raise TypeError
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for n,d in map(_exact_ratio, values):
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count += 1
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partials[d] = partials_get(d, 0) + n
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2016-02-06 09:36:57 +00:00
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if None in partials:
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2018-12-31 23:25:26 +00:00
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# The sum will be a NAN or INF. We can ignore all the finite
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# partials, and just look at this special one.
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total = partials[None]
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assert not _isfinite(total)
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else:
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# Sum all the partial sums using builtin sum.
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# FIXME is this faster if we sum them in order of the denominator?
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total = sum(Fraction(n, d) for d, n in sorted(partials.items()))
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return (T, total, count)
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def _isfinite(x):
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try:
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return x.is_finite() # Likely a Decimal.
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except AttributeError:
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return math.isfinite(x) # Coerces to float first.
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def _coerce(T, S):
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"""Coerce types T and S to a common type, or raise TypeError.
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Coercion rules are currently an implementation detail. See the CoerceTest
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test class in test_statistics for details.
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"""
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# See http://bugs.python.org/issue24068.
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assert T is not bool, "initial type T is bool"
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# If the types are the same, no need to coerce anything. Put this
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# first, so that the usual case (no coercion needed) happens as soon
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# as possible.
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if T is S: return T
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# Mixed int & other coerce to the other type.
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if S is int or S is bool: return T
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if T is int: return S
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# If one is a (strict) subclass of the other, coerce to the subclass.
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if issubclass(S, T): return S
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if issubclass(T, S): return T
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# Ints coerce to the other type.
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if issubclass(T, int): return S
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if issubclass(S, int): return T
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# Mixed fraction & float coerces to float (or float subclass).
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if issubclass(T, Fraction) and issubclass(S, float):
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return S
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if issubclass(T, float) and issubclass(S, Fraction):
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return T
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# Any other combination is disallowed.
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msg = "don't know how to coerce %s and %s"
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raise TypeError(msg % (T.__name__, S.__name__))
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2016-02-06 09:36:57 +00:00
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def _exact_ratio(x):
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2018-12-31 23:25:26 +00:00
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"""Return Real number x to exact (numerator, denominator) pair.
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2016-02-06 09:36:57 +00:00
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>>> _exact_ratio(0.25)
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(1, 4)
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x is expected to be an int, Fraction, Decimal or float.
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"""
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try:
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2018-12-31 23:25:26 +00:00
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# Optimise the common case of floats. We expect that the most often
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# used numeric type will be builtin floats, so try to make this as
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# fast as possible.
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if type(x) is float or type(x) is Decimal:
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return x.as_integer_ratio()
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2016-02-06 09:36:57 +00:00
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try:
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2018-12-31 23:25:26 +00:00
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# x may be an int, Fraction, or Integral ABC.
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2016-02-06 09:36:57 +00:00
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return (x.numerator, x.denominator)
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except AttributeError:
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try:
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2018-12-31 23:25:26 +00:00
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# x may be a float or Decimal subclass.
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2016-02-06 09:36:57 +00:00
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return x.as_integer_ratio()
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except AttributeError:
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2018-12-31 23:25:26 +00:00
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# Just give up?
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pass
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2016-02-06 09:36:57 +00:00
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except (OverflowError, ValueError):
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2018-12-31 23:25:26 +00:00
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# float NAN or INF.
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assert not _isfinite(x)
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2016-02-06 09:36:57 +00:00
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return (x, None)
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2018-12-31 23:25:26 +00:00
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msg = "can't convert type '{}' to numerator/denominator"
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raise TypeError(msg.format(type(x).__name__))
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def _convert(value, T):
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"""Convert value to given numeric type T."""
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if type(value) is T:
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# This covers the cases where T is Fraction, or where value is
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# a NAN or INF (Decimal or float).
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return value
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if issubclass(T, int) and value.denominator != 1:
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T = float
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try:
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# FIXME: what do we do if this overflows?
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return T(value)
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except TypeError:
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if issubclass(T, Decimal):
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return T(value.numerator)/T(value.denominator)
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else:
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raise
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2016-02-06 09:36:57 +00:00
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def _counts(data):
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# Generate a table of sorted (value, frequency) pairs.
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table = collections.Counter(iter(data)).most_common()
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if not table:
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return table
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# Extract the values with the highest frequency.
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maxfreq = table[0][1]
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for i in range(1, len(table)):
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if table[i][1] != maxfreq:
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table = table[:i]
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break
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return table
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2018-12-31 23:25:26 +00:00
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def _find_lteq(a, x):
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'Locate the leftmost value exactly equal to x'
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i = bisect_left(a, x)
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if i != len(a) and a[i] == x:
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return i
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raise ValueError
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def _find_rteq(a, l, x):
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'Locate the rightmost value exactly equal to x'
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i = bisect_right(a, x, lo=l)
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if i != (len(a)+1) and a[i-1] == x:
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return i-1
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raise ValueError
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def _fail_neg(values, errmsg='negative value'):
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"""Iterate over values, failing if any are less than zero."""
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for x in values:
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if x < 0:
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raise StatisticsError(errmsg)
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yield x
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2016-02-06 09:36:57 +00:00
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# === Measures of central tendency (averages) ===
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def mean(data):
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"""Return the sample arithmetic mean of data.
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>>> mean([1, 2, 3, 4, 4])
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2.8
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>>> from fractions import Fraction as F
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>>> mean([F(3, 7), F(1, 21), F(5, 3), F(1, 3)])
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Fraction(13, 21)
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>>> from decimal import Decimal as D
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>>> mean([D("0.5"), D("0.75"), D("0.625"), D("0.375")])
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Decimal('0.5625')
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If ``data`` is empty, StatisticsError will be raised.
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"""
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if iter(data) is data:
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data = list(data)
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n = len(data)
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if n < 1:
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raise StatisticsError('mean requires at least one data point')
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2018-12-31 23:25:26 +00:00
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T, total, count = _sum(data)
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assert count == n
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return _convert(total/n, T)
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def harmonic_mean(data):
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"""Return the harmonic mean of data.
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The harmonic mean, sometimes called the subcontrary mean, is the
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reciprocal of the arithmetic mean of the reciprocals of the data,
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and is often appropriate when averaging quantities which are rates
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or ratios, for example speeds. Example:
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Suppose an investor purchases an equal value of shares in each of
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three companies, with P/E (price/earning) ratios of 2.5, 3 and 10.
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What is the average P/E ratio for the investor's portfolio?
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>>> harmonic_mean([2.5, 3, 10]) # For an equal investment portfolio.
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3.6
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Using the arithmetic mean would give an average of about 5.167, which
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is too high.
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If ``data`` is empty, or any element is less than zero,
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``harmonic_mean`` will raise ``StatisticsError``.
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"""
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# For a justification for using harmonic mean for P/E ratios, see
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# http://fixthepitch.pellucid.com/comps-analysis-the-missing-harmony-of-summary-statistics/
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# http://papers.ssrn.com/sol3/papers.cfm?abstract_id=2621087
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if iter(data) is data:
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data = list(data)
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errmsg = 'harmonic mean does not support negative values'
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n = len(data)
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if n < 1:
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raise StatisticsError('harmonic_mean requires at least one data point')
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elif n == 1:
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x = data[0]
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if isinstance(x, (numbers.Real, Decimal)):
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if x < 0:
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raise StatisticsError(errmsg)
|
|
|
|
return x
|
|
|
|
else:
|
|
|
|
raise TypeError('unsupported type')
|
|
|
|
try:
|
|
|
|
T, total, count = _sum(1/x for x in _fail_neg(data, errmsg))
|
|
|
|
except ZeroDivisionError:
|
|
|
|
return 0
|
|
|
|
assert count == n
|
|
|
|
return _convert(n/total, T)
|
2016-02-06 09:36:57 +00:00
|
|
|
|
|
|
|
|
|
|
|
# FIXME: investigate ways to calculate medians without sorting? Quickselect?
|
|
|
|
def median(data):
|
|
|
|
"""Return the median (middle value) of numeric data.
|
|
|
|
|
|
|
|
When the number of data points is odd, return the middle data point.
|
|
|
|
When the number of data points is even, the median is interpolated by
|
|
|
|
taking the average of the two middle values:
|
|
|
|
|
|
|
|
>>> median([1, 3, 5])
|
|
|
|
3
|
|
|
|
>>> median([1, 3, 5, 7])
|
|
|
|
4.0
|
|
|
|
|
|
|
|
"""
|
|
|
|
data = sorted(data)
|
|
|
|
n = len(data)
|
|
|
|
if n == 0:
|
|
|
|
raise StatisticsError("no median for empty data")
|
|
|
|
if n%2 == 1:
|
|
|
|
return data[n//2]
|
|
|
|
else:
|
|
|
|
i = n//2
|
|
|
|
return (data[i - 1] + data[i])/2
|
|
|
|
|
|
|
|
|
|
|
|
def median_low(data):
|
|
|
|
"""Return the low median of numeric data.
|
|
|
|
|
|
|
|
When the number of data points is odd, the middle value is returned.
|
|
|
|
When it is even, the smaller of the two middle values is returned.
|
|
|
|
|
|
|
|
>>> median_low([1, 3, 5])
|
|
|
|
3
|
|
|
|
>>> median_low([1, 3, 5, 7])
|
|
|
|
3
|
|
|
|
|
|
|
|
"""
|
|
|
|
data = sorted(data)
|
|
|
|
n = len(data)
|
|
|
|
if n == 0:
|
|
|
|
raise StatisticsError("no median for empty data")
|
|
|
|
if n%2 == 1:
|
|
|
|
return data[n//2]
|
|
|
|
else:
|
|
|
|
return data[n//2 - 1]
|
|
|
|
|
|
|
|
|
|
|
|
def median_high(data):
|
|
|
|
"""Return the high median of data.
|
|
|
|
|
|
|
|
When the number of data points is odd, the middle value is returned.
|
|
|
|
When it is even, the larger of the two middle values is returned.
|
|
|
|
|
|
|
|
>>> median_high([1, 3, 5])
|
|
|
|
3
|
|
|
|
>>> median_high([1, 3, 5, 7])
|
|
|
|
5
|
|
|
|
|
|
|
|
"""
|
|
|
|
data = sorted(data)
|
|
|
|
n = len(data)
|
|
|
|
if n == 0:
|
|
|
|
raise StatisticsError("no median for empty data")
|
|
|
|
return data[n//2]
|
|
|
|
|
|
|
|
|
|
|
|
def median_grouped(data, interval=1):
|
2018-12-31 23:25:26 +00:00
|
|
|
"""Return the 50th percentile (median) of grouped continuous data.
|
2016-02-06 09:36:57 +00:00
|
|
|
|
|
|
|
>>> median_grouped([1, 2, 2, 3, 4, 4, 4, 4, 4, 5])
|
|
|
|
3.7
|
|
|
|
>>> median_grouped([52, 52, 53, 54])
|
|
|
|
52.5
|
|
|
|
|
|
|
|
This calculates the median as the 50th percentile, and should be
|
|
|
|
used when your data is continuous and grouped. In the above example,
|
|
|
|
the values 1, 2, 3, etc. actually represent the midpoint of classes
|
|
|
|
0.5-1.5, 1.5-2.5, 2.5-3.5, etc. The middle value falls somewhere in
|
|
|
|
class 3.5-4.5, and interpolation is used to estimate it.
|
|
|
|
|
|
|
|
Optional argument ``interval`` represents the class interval, and
|
|
|
|
defaults to 1. Changing the class interval naturally will change the
|
|
|
|
interpolated 50th percentile value:
|
|
|
|
|
|
|
|
>>> median_grouped([1, 3, 3, 5, 7], interval=1)
|
|
|
|
3.25
|
|
|
|
>>> median_grouped([1, 3, 3, 5, 7], interval=2)
|
|
|
|
3.5
|
|
|
|
|
|
|
|
This function does not check whether the data points are at least
|
|
|
|
``interval`` apart.
|
|
|
|
"""
|
|
|
|
data = sorted(data)
|
|
|
|
n = len(data)
|
|
|
|
if n == 0:
|
|
|
|
raise StatisticsError("no median for empty data")
|
|
|
|
elif n == 1:
|
|
|
|
return data[0]
|
|
|
|
# Find the value at the midpoint. Remember this corresponds to the
|
|
|
|
# centre of the class interval.
|
|
|
|
x = data[n//2]
|
|
|
|
for obj in (x, interval):
|
|
|
|
if isinstance(obj, (str, bytes)):
|
|
|
|
raise TypeError('expected number but got %r' % obj)
|
|
|
|
try:
|
|
|
|
L = x - interval/2 # The lower limit of the median interval.
|
|
|
|
except TypeError:
|
|
|
|
# Mixed type. For now we just coerce to float.
|
|
|
|
L = float(x) - float(interval)/2
|
2018-12-31 23:25:26 +00:00
|
|
|
|
|
|
|
# Uses bisection search to search for x in data with log(n) time complexity
|
|
|
|
# Find the position of leftmost occurrence of x in data
|
|
|
|
l1 = _find_lteq(data, x)
|
|
|
|
# Find the position of rightmost occurrence of x in data[l1...len(data)]
|
|
|
|
# Assuming always l1 <= l2
|
|
|
|
l2 = _find_rteq(data, l1, x)
|
|
|
|
cf = l1
|
|
|
|
f = l2 - l1 + 1
|
2016-02-06 09:36:57 +00:00
|
|
|
return L + interval*(n/2 - cf)/f
|
|
|
|
|
|
|
|
|
|
|
|
def mode(data):
|
|
|
|
"""Return the most common data point from discrete or nominal data.
|
|
|
|
|
|
|
|
``mode`` assumes discrete data, and returns a single value. This is the
|
|
|
|
standard treatment of the mode as commonly taught in schools:
|
|
|
|
|
|
|
|
>>> mode([1, 1, 2, 3, 3, 3, 3, 4])
|
|
|
|
3
|
|
|
|
|
|
|
|
This also works with nominal (non-numeric) data:
|
|
|
|
|
|
|
|
>>> mode(["red", "blue", "blue", "red", "green", "red", "red"])
|
|
|
|
'red'
|
|
|
|
|
|
|
|
If there is not exactly one most common value, ``mode`` will raise
|
|
|
|
StatisticsError.
|
|
|
|
"""
|
|
|
|
# Generate a table of sorted (value, frequency) pairs.
|
|
|
|
table = _counts(data)
|
|
|
|
if len(table) == 1:
|
|
|
|
return table[0][0]
|
|
|
|
elif table:
|
|
|
|
raise StatisticsError(
|
|
|
|
'no unique mode; found %d equally common values' % len(table)
|
|
|
|
)
|
|
|
|
else:
|
|
|
|
raise StatisticsError('no mode for empty data')
|
|
|
|
|
|
|
|
|
|
|
|
# === Measures of spread ===
|
|
|
|
|
|
|
|
# See http://mathworld.wolfram.com/Variance.html
|
|
|
|
# http://mathworld.wolfram.com/SampleVariance.html
|
|
|
|
# http://en.wikipedia.org/wiki/Algorithms_for_calculating_variance
|
|
|
|
#
|
|
|
|
# Under no circumstances use the so-called "computational formula for
|
|
|
|
# variance", as that is only suitable for hand calculations with a small
|
|
|
|
# amount of low-precision data. It has terrible numeric properties.
|
|
|
|
#
|
|
|
|
# See a comparison of three computational methods here:
|
|
|
|
# http://www.johndcook.com/blog/2008/09/26/comparing-three-methods-of-computing-standard-deviation/
|
|
|
|
|
|
|
|
def _ss(data, c=None):
|
|
|
|
"""Return sum of square deviations of sequence data.
|
|
|
|
|
|
|
|
If ``c`` is None, the mean is calculated in one pass, and the deviations
|
|
|
|
from the mean are calculated in a second pass. Otherwise, deviations are
|
|
|
|
calculated from ``c`` as given. Use the second case with care, as it can
|
|
|
|
lead to garbage results.
|
|
|
|
"""
|
|
|
|
if c is None:
|
|
|
|
c = mean(data)
|
2018-12-31 23:25:26 +00:00
|
|
|
T, total, count = _sum((x-c)**2 for x in data)
|
2016-02-06 09:36:57 +00:00
|
|
|
# The following sum should mathematically equal zero, but due to rounding
|
|
|
|
# error may not.
|
2018-12-31 23:25:26 +00:00
|
|
|
U, total2, count2 = _sum((x-c) for x in data)
|
|
|
|
assert T == U and count == count2
|
|
|
|
total -= total2**2/len(data)
|
|
|
|
assert not total < 0, 'negative sum of square deviations: %f' % total
|
|
|
|
return (T, total)
|
2016-02-06 09:36:57 +00:00
|
|
|
|
|
|
|
|
|
|
|
def variance(data, xbar=None):
|
|
|
|
"""Return the sample variance of data.
|
|
|
|
|
|
|
|
data should be an iterable of Real-valued numbers, with at least two
|
|
|
|
values. The optional argument xbar, if given, should be the mean of
|
|
|
|
the data. If it is missing or None, the mean is automatically calculated.
|
|
|
|
|
|
|
|
Use this function when your data is a sample from a population. To
|
|
|
|
calculate the variance from the entire population, see ``pvariance``.
|
|
|
|
|
|
|
|
Examples:
|
|
|
|
|
|
|
|
>>> data = [2.75, 1.75, 1.25, 0.25, 0.5, 1.25, 3.5]
|
|
|
|
>>> variance(data)
|
|
|
|
1.3720238095238095
|
|
|
|
|
|
|
|
If you have already calculated the mean of your data, you can pass it as
|
|
|
|
the optional second argument ``xbar`` to avoid recalculating it:
|
|
|
|
|
|
|
|
>>> m = mean(data)
|
|
|
|
>>> variance(data, m)
|
|
|
|
1.3720238095238095
|
|
|
|
|
|
|
|
This function does not check that ``xbar`` is actually the mean of
|
|
|
|
``data``. Giving arbitrary values for ``xbar`` may lead to invalid or
|
|
|
|
impossible results.
|
|
|
|
|
|
|
|
Decimals and Fractions are supported:
|
|
|
|
|
|
|
|
>>> from decimal import Decimal as D
|
|
|
|
>>> variance([D("27.5"), D("30.25"), D("30.25"), D("34.5"), D("41.75")])
|
|
|
|
Decimal('31.01875')
|
|
|
|
|
|
|
|
>>> from fractions import Fraction as F
|
|
|
|
>>> variance([F(1, 6), F(1, 2), F(5, 3)])
|
|
|
|
Fraction(67, 108)
|
|
|
|
|
|
|
|
"""
|
|
|
|
if iter(data) is data:
|
|
|
|
data = list(data)
|
|
|
|
n = len(data)
|
|
|
|
if n < 2:
|
|
|
|
raise StatisticsError('variance requires at least two data points')
|
2018-12-31 23:25:26 +00:00
|
|
|
T, ss = _ss(data, xbar)
|
|
|
|
return _convert(ss/(n-1), T)
|
2016-02-06 09:36:57 +00:00
|
|
|
|
|
|
|
|
|
|
|
def pvariance(data, mu=None):
|
|
|
|
"""Return the population variance of ``data``.
|
|
|
|
|
|
|
|
data should be an iterable of Real-valued numbers, with at least one
|
|
|
|
value. The optional argument mu, if given, should be the mean of
|
|
|
|
the data. If it is missing or None, the mean is automatically calculated.
|
|
|
|
|
|
|
|
Use this function to calculate the variance from the entire population.
|
|
|
|
To estimate the variance from a sample, the ``variance`` function is
|
|
|
|
usually a better choice.
|
|
|
|
|
|
|
|
Examples:
|
|
|
|
|
|
|
|
>>> data = [0.0, 0.25, 0.25, 1.25, 1.5, 1.75, 2.75, 3.25]
|
|
|
|
>>> pvariance(data)
|
|
|
|
1.25
|
|
|
|
|
|
|
|
If you have already calculated the mean of the data, you can pass it as
|
|
|
|
the optional second argument to avoid recalculating it:
|
|
|
|
|
|
|
|
>>> mu = mean(data)
|
|
|
|
>>> pvariance(data, mu)
|
|
|
|
1.25
|
|
|
|
|
|
|
|
This function does not check that ``mu`` is actually the mean of ``data``.
|
|
|
|
Giving arbitrary values for ``mu`` may lead to invalid or impossible
|
|
|
|
results.
|
|
|
|
|
|
|
|
Decimals and Fractions are supported:
|
|
|
|
|
|
|
|
>>> from decimal import Decimal as D
|
|
|
|
>>> pvariance([D("27.5"), D("30.25"), D("30.25"), D("34.5"), D("41.75")])
|
|
|
|
Decimal('24.815')
|
|
|
|
|
|
|
|
>>> from fractions import Fraction as F
|
|
|
|
>>> pvariance([F(1, 4), F(5, 4), F(1, 2)])
|
|
|
|
Fraction(13, 72)
|
|
|
|
|
|
|
|
"""
|
|
|
|
if iter(data) is data:
|
|
|
|
data = list(data)
|
|
|
|
n = len(data)
|
|
|
|
if n < 1:
|
|
|
|
raise StatisticsError('pvariance requires at least one data point')
|
2018-12-31 23:25:26 +00:00
|
|
|
T, ss = _ss(data, mu)
|
|
|
|
return _convert(ss/n, T)
|
2016-02-06 09:36:57 +00:00
|
|
|
|
|
|
|
|
|
|
|
def stdev(data, xbar=None):
|
|
|
|
"""Return the square root of the sample variance.
|
|
|
|
|
|
|
|
See ``variance`` for arguments and other details.
|
|
|
|
|
|
|
|
>>> stdev([1.5, 2.5, 2.5, 2.75, 3.25, 4.75])
|
|
|
|
1.0810874155219827
|
|
|
|
|
|
|
|
"""
|
|
|
|
var = variance(data, xbar)
|
|
|
|
try:
|
|
|
|
return var.sqrt()
|
|
|
|
except AttributeError:
|
|
|
|
return math.sqrt(var)
|
|
|
|
|
|
|
|
|
|
|
|
def pstdev(data, mu=None):
|
|
|
|
"""Return the square root of the population variance.
|
|
|
|
|
|
|
|
See ``pvariance`` for arguments and other details.
|
|
|
|
|
|
|
|
>>> pstdev([1.5, 2.5, 2.5, 2.75, 3.25, 4.75])
|
|
|
|
0.986893273527251
|
|
|
|
|
|
|
|
"""
|
|
|
|
var = pvariance(data, mu)
|
|
|
|
try:
|
|
|
|
return var.sqrt()
|
|
|
|
except AttributeError:
|
|
|
|
return math.sqrt(var)
|