321 lines
12 KiB
Python
321 lines
12 KiB
Python
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#
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# AllOrNothing.py : all-or-nothing package transformations
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#
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# Part of the Python Cryptography Toolkit
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#
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# Written by Andrew M. Kuchling and others
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#
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# ===================================================================
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# The contents of this file are dedicated to the public domain. To
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# the extent that dedication to the public domain is not available,
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# everyone is granted a worldwide, perpetual, royalty-free,
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# non-exclusive license to exercise all rights associated with the
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# contents of this file for any purpose whatsoever.
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# No rights are reserved.
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#
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# THE SOFTWARE IS PROVIDED "AS IS", WITHOUT WARRANTY OF ANY KIND,
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# EXPRESS OR IMPLIED, INCLUDING BUT NOT LIMITED TO THE WARRANTIES OF
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# MERCHANTABILITY, FITNESS FOR A PARTICULAR PURPOSE AND
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# NONINFRINGEMENT. IN NO EVENT SHALL THE AUTHORS OR COPYRIGHT HOLDERS
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# BE LIABLE FOR ANY CLAIM, DAMAGES OR OTHER LIABILITY, WHETHER IN AN
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# ACTION OF CONTRACT, TORT OR OTHERWISE, ARISING FROM, OUT OF OR IN
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# CONNECTION WITH THE SOFTWARE OR THE USE OR OTHER DEALINGS IN THE
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# SOFTWARE.
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# ===================================================================
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"""This file implements all-or-nothing package transformations.
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An all-or-nothing package transformation is one in which some text is
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transformed into message blocks, such that all blocks must be obtained before
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the reverse transformation can be applied. Thus, if any blocks are corrupted
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or lost, the original message cannot be reproduced.
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An all-or-nothing package transformation is not encryption, although a block
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cipher algorithm is used. The encryption key is randomly generated and is
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extractable from the message blocks.
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This class implements the All-Or-Nothing package transformation algorithm
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described in:
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Ronald L. Rivest. "All-Or-Nothing Encryption and The Package Transform"
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http://theory.lcs.mit.edu/~rivest/fusion.pdf
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"""
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__revision__ = "$Id$"
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import operator
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import sys
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from Crypto.Util.number import bytes_to_long, long_to_bytes
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from Crypto.Util.py3compat import *
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from functools import reduce
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def isInt(x):
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test = 0
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try:
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test += x
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except TypeError:
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return 0
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return 1
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class AllOrNothing:
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"""Class implementing the All-or-Nothing package transform.
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Methods for subclassing:
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_inventkey(key_size):
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Returns a randomly generated key. Subclasses can use this to
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implement better random key generating algorithms. The default
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algorithm is probably not very cryptographically secure.
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"""
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def __init__(self, ciphermodule, mode=None, IV=None):
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"""AllOrNothing(ciphermodule, mode=None, IV=None)
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ciphermodule is a module implementing the cipher algorithm to
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use. It must provide the PEP272 interface.
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Note that the encryption key is randomly generated
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automatically when needed. Optional arguments mode and IV are
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passed directly through to the ciphermodule.new() method; they
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are the feedback mode and initialization vector to use. All
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three arguments must be the same for the object used to create
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the digest, and to undigest'ify the message blocks.
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"""
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self.__ciphermodule = ciphermodule
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self.__mode = mode
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self.__IV = IV
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self.__key_size = ciphermodule.key_size
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if not isInt(self.__key_size) or self.__key_size==0:
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self.__key_size = 16
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__K0digit = bchr(0x69)
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def digest(self, text):
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"""digest(text:string) : [string]
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Perform the All-or-Nothing package transform on the given
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string. Output is a list of message blocks describing the
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transformed text, where each block is a string of bit length equal
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to the ciphermodule's block_size.
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"""
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# generate a random session key and K0, the key used to encrypt the
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# hash blocks. Rivest calls this a fixed, publically-known encryption
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# key, but says nothing about the security implications of this key or
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# how to choose it.
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key = self._inventkey(self.__key_size)
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K0 = self.__K0digit * self.__key_size
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# we need two cipher objects here, one that is used to encrypt the
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# message blocks and one that is used to encrypt the hashes. The
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# former uses the randomly generated key, while the latter uses the
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# well-known key.
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mcipher = self.__newcipher(key)
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hcipher = self.__newcipher(K0)
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# Pad the text so that its length is a multiple of the cipher's
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# block_size. Pad with trailing spaces, which will be eliminated in
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# the undigest() step.
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block_size = self.__ciphermodule.block_size
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padbytes = block_size - (len(text) % block_size)
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text = text + b(' ') * padbytes
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# Run through the algorithm:
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# s: number of message blocks (size of text / block_size)
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# input sequence: m1, m2, ... ms
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# random key K' (`key' in the code)
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# Compute output sequence: m'1, m'2, ... m's' for s' = s + 1
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# Let m'i = mi ^ E(K', i) for i = 1, 2, 3, ..., s
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# Let m's' = K' ^ h1 ^ h2 ^ ... hs
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# where hi = E(K0, m'i ^ i) for i = 1, 2, ... s
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#
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# The one complication I add is that the last message block is hard
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# coded to the number of padbytes added, so that these can be stripped
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# during the undigest() step
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s = divmod(len(text), block_size)[0]
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blocks = []
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hashes = []
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for i in range(1, s+1):
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start = (i-1) * block_size
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end = start + block_size
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mi = text[start:end]
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assert len(mi) == block_size
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cipherblock = mcipher.encrypt(long_to_bytes(i, block_size))
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mticki = bytes_to_long(mi) ^ bytes_to_long(cipherblock)
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blocks.append(mticki)
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# calculate the hash block for this block
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hi = hcipher.encrypt(long_to_bytes(mticki ^ i, block_size))
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hashes.append(bytes_to_long(hi))
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# Add the padbytes length as a message block
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i = i + 1
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cipherblock = mcipher.encrypt(long_to_bytes(i, block_size))
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mticki = padbytes ^ bytes_to_long(cipherblock)
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blocks.append(mticki)
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# calculate this block's hash
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hi = hcipher.encrypt(long_to_bytes(mticki ^ i, block_size))
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hashes.append(bytes_to_long(hi))
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# Now calculate the last message block of the sequence 1..s'. This
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# will contain the random session key XOR'd with all the hash blocks,
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# so that for undigest(), once all the hash blocks are calculated, the
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# session key can be trivially extracted. Calculating all the hash
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# blocks requires that all the message blocks be received, thus the
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# All-or-Nothing algorithm succeeds.
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mtick_stick = bytes_to_long(key) ^ reduce(operator.xor, hashes)
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blocks.append(mtick_stick)
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# we convert the blocks to strings since in Python, byte sequences are
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# always represented as strings. This is more consistent with the
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# model that encryption and hash algorithms always operate on strings.
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return [long_to_bytes(i,self.__ciphermodule.block_size) for i in blocks]
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def undigest(self, blocks):
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"""undigest(blocks : [string]) : string
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Perform the reverse package transformation on a list of message
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blocks. Note that the ciphermodule used for both transformations
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must be the same. blocks is a list of strings of bit length
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equal to the ciphermodule's block_size.
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"""
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# better have at least 2 blocks, for the padbytes package and the hash
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# block accumulator
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if len(blocks) < 2:
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raise ValueError("List must be at least length 2.")
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# blocks is a list of strings. We need to deal with them as long
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# integers
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blocks = list(map(bytes_to_long, blocks))
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# Calculate the well-known key, to which the hash blocks are
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# encrypted, and create the hash cipher.
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K0 = self.__K0digit * self.__key_size
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hcipher = self.__newcipher(K0)
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block_size = self.__ciphermodule.block_size
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# Since we have all the blocks (or this method would have been called
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# prematurely), we can calculate all the hash blocks.
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hashes = []
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for i in range(1, len(blocks)):
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mticki = blocks[i-1] ^ i
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hi = hcipher.encrypt(long_to_bytes(mticki, block_size))
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hashes.append(bytes_to_long(hi))
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# now we can calculate K' (key). remember the last block contains
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# m's' which we don't include here
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key = blocks[-1] ^ reduce(operator.xor, hashes)
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# and now we can create the cipher object
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mcipher = self.__newcipher(long_to_bytes(key, self.__key_size))
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# And we can now decode the original message blocks
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parts = []
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for i in range(1, len(blocks)):
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cipherblock = mcipher.encrypt(long_to_bytes(i, block_size))
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mi = blocks[i-1] ^ bytes_to_long(cipherblock)
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parts.append(mi)
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# The last message block contains the number of pad bytes appended to
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# the original text string, such that its length was an even multiple
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# of the cipher's block_size. This number should be small enough that
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# the conversion from long integer to integer should never overflow
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padbytes = int(parts[-1])
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text = b('').join(map(long_to_bytes, parts[:-1]))
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return text[:-padbytes]
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def _inventkey(self, key_size):
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# Return key_size random bytes
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from Crypto import Random
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return Random.new().read(key_size)
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def __newcipher(self, key):
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if self.__mode is None and self.__IV is None:
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return self.__ciphermodule.new(key)
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elif self.__IV is None:
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return self.__ciphermodule.new(key, self.__mode)
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else:
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return self.__ciphermodule.new(key, self.__mode, self.__IV)
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if __name__ == '__main__':
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import sys
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import getopt
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import base64
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usagemsg = '''\
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Test module usage: %(program)s [-c cipher] [-l] [-h]
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Where:
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--cipher module
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-c module
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Cipher module to use. Default: %(ciphermodule)s
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--aslong
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-l
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Print the encoded message blocks as long integers instead of base64
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encoded strings
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--help
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-h
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Print this help message
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'''
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ciphermodule = 'AES'
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aslong = 0
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def usage(code, msg=None):
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if msg:
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print(msg)
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print(usagemsg % {'program': sys.argv[0],
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'ciphermodule': ciphermodule})
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sys.exit(code)
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try:
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opts, args = getopt.getopt(sys.argv[1:],
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'c:l', ['cipher=', 'aslong'])
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except getopt.error as msg:
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usage(1, msg)
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if args:
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usage(1, 'Too many arguments')
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for opt, arg in opts:
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if opt in ('-h', '--help'):
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usage(0)
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elif opt in ('-c', '--cipher'):
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ciphermodule = arg
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elif opt in ('-l', '--aslong'):
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aslong = 1
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# ugly hack to force __import__ to give us the end-path module
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module = __import__('Crypto.Cipher.'+ciphermodule, None, None, ['new'])
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x = AllOrNothing(module)
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print('Original text:\n==========')
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print(__doc__)
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print('==========')
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msgblocks = x.digest(b(__doc__))
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print('message blocks:')
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for i, blk in zip(list(range(len(msgblocks))), msgblocks):
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# base64 adds a trailing newline
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print(' %3d' % i, end=' ')
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if aslong:
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print(bytes_to_long(blk))
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else:
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print(base64.encodestring(blk)[:-1])
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#
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# get a new undigest-only object so there's no leakage
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y = AllOrNothing(module)
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text = y.undigest(msgblocks)
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if text == b(__doc__):
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print('They match!')
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else:
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print('They differ!')
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