0x2620/openmedialibrary_platform
1
0
Fork 0
Code Issues Pull requests Releases Wiki Activity

Switch to python3

Browse source
This commit is contained in:
j 2014-09-30 18:15:32 +02:00
commit 9ba4b6a91a
5286 changed files with 677347 additions and 576888 deletions
Download patch file Download diff file Expand all files Collapse all files

30
Shared/lib/python3.4/site-packages/stdnum/iso7064/__init__.py Normal file
View file

@ -0,0 +1,30 @@
# __init__.py - functions for performing the ISO 7064 algorithms
#
# Copyright (C) 2010, 2012 Arthur de Jong
#
# This library is free software; you can redistribute it and/or
# modify it under the terms of the GNU Lesser General Public
# License as published by the Free Software Foundation; either
# version 2.1 of the License, or (at your option) any later version.
#
# This library is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
# Lesser General Public License for more details.
#
# You should have received a copy of the GNU Lesser General Public
# License along with this library; if not, write to the Free Software
# Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA
# 02110-1301 USA
"""Collection of the ISO 7064 algorithms.
This package provides a number of modules for calculation and verification
of numbers using one of the ISO 7064 algorithms.
Note that these functions were not implemented using the ISO text itself
because the text is not available for free. These functions were
implemented based on information on the algorithms found online and some
reverse engineering. If anyone can provide a legal copy of the ISO/IEC
7064 standard these functions can be validated and perhaps improved.
"""

71
Shared/lib/python3.4/site-packages/stdnum/iso7064/mod_11_10.py Normal file
View file

@ -0,0 +1,71 @@
# mod_11_10.py - functions for performing the ISO 7064 Mod 11, 10 algorithm
#
# Copyright (C) 2010, 2011, 2012, 2013 Arthur de Jong
#
# This library is free software; you can redistribute it and/or
# modify it under the terms of the GNU Lesser General Public
# License as published by the Free Software Foundation; either
# version 2.1 of the License, or (at your option) any later version.
#
# This library is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
# Lesser General Public License for more details.
#
# You should have received a copy of the GNU Lesser General Public
# License along with this library; if not, write to the Free Software
# Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA
# 02110-1301 USA
"""The ISO 7064 Mod 11, 10 algorithm.
The Mod 11, 10 algorithm uses a number of calculations modulo 11 and 10 to
determine a checksum.
For a module that can do generic Mod x+1, x calculations see the
:mod:`stdnum.iso7064.mod_37_36` module.
>>> calc_check_digit('79462')
'3'
>>> validate('794623')
'794623'
>>> calc_check_digit('00200667308')
'5'
>>> validate('002006673085')
'002006673085'
"""
from stdnum.exceptions import *
def checksum(number):
"""Calculate the checksum. A valid number should have a checksum of 1."""
check = 5
for n in number:
check = (((check or 10) * 2) % 11 + int(n)) % 10
return check
def calc_check_digit(number):
"""With the provided number, calculate the extra digit that should be
appended to make it a valid number."""
return str((1 - ((checksum(number) or 10) * 2) % 11) % 10)
def validate(number):
"""Checks whether the check digit is valid."""
try:
valid = checksum(number) == 1
except:
raise InvalidFormat()
if not valid:
raise InvalidChecksum()
return number
def is_valid(number):
"""Checks whether the check digit is valid."""
try:
return bool(validate(number))
except ValidationError:
return False

74
Shared/lib/python3.4/site-packages/stdnum/iso7064/mod_11_2.py Normal file
View file

@ -0,0 +1,74 @@
# mod_11_2.py - functions for performing the ISO 7064 Mod 11, 2 algorithm
#
# Copyright (C) 2010, 2011, 2012, 2013 Arthur de Jong
#
# This library is free software; you can redistribute it and/or
# modify it under the terms of the GNU Lesser General Public
# License as published by the Free Software Foundation; either
# version 2.1 of the License, or (at your option) any later version.
#
# This library is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
# Lesser General Public License for more details.
#
# You should have received a copy of the GNU Lesser General Public
# License along with this library; if not, write to the Free Software
# Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA
# 02110-1301 USA
"""The ISO 7064 Mod 11, 2 algorithm.
The Mod 11, 2 algorithm is a simple module 11 checksum where the check
digit can be an X to make the number valid.
For a module that can do generic Mod x, 2 calculations see the
:mod:`stdnum.iso7064.mod_37_2` module.
>>> calc_check_digit('0794')
'0'
>>> validate('07940')
'07940'
>>> calc_check_digit('079')
'X'
>>> validate('079X')
'079X'
>>> checksum('079X')
1
"""
from stdnum.exceptions import *
def checksum(number):
"""Calculate the checksum. A valid number should have a checksum of 1."""
check = 0
for n in number:
check = (2 * check + int(10 if n == 'X' else n)) % 11
return check
def calc_check_digit(number):
"""With the provided number, calculate the extra digit that should be
appended to make it a valid number."""
c = (1 - 2 * checksum(number)) % 11
return 'X' if c == 10 else str(c)
def validate(number):
"""Checks whether the check digit is valid."""
try:
valid = checksum(number) == 1
except:
raise InvalidFormat()
if not valid:
raise InvalidChecksum()
return number
def is_valid(number):
"""Checks whether the check digit is valid."""
try:
return bool(validate(number))
except ValidationError:
return False

78
Shared/lib/python3.4/site-packages/stdnum/iso7064/mod_37_2.py Normal file
View file

@ -0,0 +1,78 @@
# mod_37_2.py - functions for performing the ISO 7064 Mod 37, 2 algorithm
#
# Copyright (C) 2010, 2011, 2012, 2013 Arthur de Jong
#
# This library is free software; you can redistribute it and/or
# modify it under the terms of the GNU Lesser General Public
# License as published by the Free Software Foundation; either
# version 2.1 of the License, or (at your option) any later version.
#
# This library is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
# Lesser General Public License for more details.
#
# You should have received a copy of the GNU Lesser General Public
# License along with this library; if not, write to the Free Software
# Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA
# 02110-1301 USA
"""The ISO 7064 Mod 37, 2 algorithm.
The Mod 37, 2 checksum can be used for alphanumeric numbers and the check
digit may also be numeric, a letter or '*'.
>>> calc_check_digit('G123489654321')
'Y'
>>> validate('G123489654321Y')
'G123489654321Y'
>>> checksum('G123489654321Y')
1
By changing the alphabet this can be turned into any Mod x, 2
algorithm. For example Mod 11, 2:
>>> calc_check_digit('079', alphabet='0123456789X')
'X'
>>> validate('079X', alphabet='0123456789X')
'079X'
>>> checksum('079X', alphabet='0123456789X')
1
"""
from stdnum.exceptions import *
def checksum(number, alphabet='0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ*'):
"""Calculate the checksum. A valid number should have a checksum of 1."""
modulus = len(alphabet)
check = 0
for n in number:
check = (2 * check + alphabet.index(n)) % modulus
return check
def calc_check_digit(number, alphabet='0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ*'):
"""With the provided number, calculate the extra digit that should be
appended to make it a valid number."""
modulus = len(alphabet)
return alphabet[(1 - 2 * checksum(number, alphabet)) % modulus]
def validate(number, alphabet='0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ*'):
"""Checks whether the check digit is valid."""
try:
valid = checksum(number, alphabet) == 1
except:
raise InvalidFormat()
if not valid:
raise InvalidChecksum()
return number
def is_valid(number, alphabet='0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ*'):
"""Checks whether the check digit is valid."""
try:
return bool(validate(number, alphabet))
except ValidationError:
return False

76
Shared/lib/python3.4/site-packages/stdnum/iso7064/mod_37_36.py Normal file
View file

@ -0,0 +1,76 @@
# mod_37_36.py - functions for performing the ISO 7064 Mod 37, 36 algorithm
#
# Copyright (C) 2010, 2011, 2012, 2013 Arthur de Jong
#
# This library is free software; you can redistribute it and/or
# modify it under the terms of the GNU Lesser General Public
# License as published by the Free Software Foundation; either
# version 2.1 of the License, or (at your option) any later version.
#
# This library is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
# Lesser General Public License for more details.
#
# You should have received a copy of the GNU Lesser General Public
# License along with this library; if not, write to the Free Software
# Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA
# 02110-1301 USA
"""The ISO 7064 Mod 37, 36 algorithm.
The Mod 37, 36 algorithm uses an alphanumeric check digit and the number
itself may also contain letters.
>>> checksum('A12425GABC1234002M')
1
>>> calc_check_digit('A12425GABC1234002')
'M'
>>> validate('A12425GABC1234002M')
'A12425GABC1234002M'
By changing the alphabet this can be turned into any Mod x+1, x
algorithm. For example Mod 11, 10:
>>> calc_check_digit('00200667308', alphabet='0123456789')
'5'
>>> validate('002006673085', alphabet='0123456789')
'002006673085'
"""
from stdnum.exceptions import *
def checksum(number, alphabet='0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ'):
"""Calculate the checksum. A valid number should have a checksum of 1."""
modulus = len(alphabet)
check = modulus // 2
for n in number:
check = (((check or modulus) * 2) % (modulus + 1) + alphabet.index(n)) % modulus
return check
def calc_check_digit(number, alphabet='0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ'):
"""With the provided number, calculate the extra digit that should be
appended to make it a valid number."""
modulus = len(alphabet)
return alphabet[(1 - ((checksum(number, alphabet) or modulus) * 2) % (modulus + 1)) % modulus]
def validate(number, alphabet='0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ'):
"""Checks whether the check digit is valid."""
try:
valid = checksum(number, alphabet) == 1
except:
raise InvalidFormat()
if not valid:
raise InvalidChecksum()
return number
def is_valid(number, alphabet='0123456789ABCDEFGHIJKLMNOPQRSTUVWXYZ'):
"""Checks whether the check digit is valid."""
try:
return bool(validate(number, alphabet))
except ValidationError:
return False

67
Shared/lib/python3.4/site-packages/stdnum/iso7064/mod_97_10.py Normal file
View file

@ -0,0 +1,67 @@
# mod_97_10.py - functions for performing the ISO 7064 Mod 97, 10 algorithm
#
# Copyright (C) 2010, 2011, 2012, 2013 Arthur de Jong
#
# This library is free software; you can redistribute it and/or
# modify it under the terms of the GNU Lesser General Public
# License as published by the Free Software Foundation; either
# version 2.1 of the License, or (at your option) any later version.
#
# This library is distributed in the hope that it will be useful,
# but WITHOUT ANY WARRANTY; without even the implied warranty of
# MERCHANTABILITY or FITNESS FOR A PARTICULAR PURPOSE. See the GNU
# Lesser General Public License for more details.
#
# You should have received a copy of the GNU Lesser General Public
# License along with this library; if not, write to the Free Software
# Foundation, Inc., 51 Franklin Street, Fifth Floor, Boston, MA
# 02110-1301 USA
"""The ISO 7064 Mod 97, 10 algorithm.
The Mod 97, 10 algorithm evaluates the whole number as an integer which is
valid if the number modulo 97 is 1. As such it has two check digits.
>>> calc_check_digits('99991234567890121414')
'90'
>>> validate('9999123456789012141490')
'9999123456789012141490'
>>> calc_check_digits('4354111611551114')
'31'
>>> validate('08686001256515001121751')
'08686001256515001121751'
>>> calc_check_digits('22181321402534321446701611')
'35'
"""
from stdnum.exceptions import *
def checksum(number):
"""Calculate the checksum. A valid number should have a checksum of 1."""
return int(number) % 97
def calc_check_digits(number):
"""With the provided number, calculate the extra digits that should be
appended to make it a valid number."""
return '%02d' % ((98 - 100 * checksum(number)) % 97)
def validate(number):
"""Checks whether the check digit is valid."""
try:
valid = checksum(number) == 1
except:
raise InvalidFormat()
if not valid:
raise InvalidChecksum()
return number
def is_valid(number):
"""Checks whether the check digit is valid."""
try:
return bool(validate(number))
except ValidationError:
return False